35k^2=25k

Solution for 35k^2=25k equation:

35k^2=25k

We move all terms to the left:

35k^2-(25k)=0

a = 35; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·35·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*35}=\frac{0}{70}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*35}=\frac{50}{70}
=5/7
$